Base | Representation |
---|---|
bin | 111010011001100101… |
… | …0010110010001111101 |
3 | 102222201012120010122221 |
4 | 1310303022112101331 |
5 | 4023321033333201 |
6 | 133340315005341 |
7 | 12026556554644 |
oct | 1646312262175 |
9 | 388635503587 |
10 | 125412402301 |
11 | 4920703907a |
12 | 20380439851 |
13 | ba9860a694 |
14 | 60da0ba35b |
15 | 33e02204a1 |
hex | 1d3329647d |
125412402301 has 2 divisors, whose sum is σ = 125412402302. Its totient is φ = 125412402300.
The previous prime is 125412402287. The next prime is 125412402331. The reversal of 125412402301 is 103204214521.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 119785902201 + 5626500100 = 346101^2 + 75010^2 .
It is an emirp because it is prime and its reverse (103204214521) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 125412402301 - 29 = 125412401789 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (125412402331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62706201150 + 62706201151.
It is an arithmetic number, because the mean of its divisors is an integer number (62706201151).
Almost surely, 2125412402301 is an apocalyptic number.
It is an amenable number.
125412402301 is a deficient number, since it is larger than the sum of its proper divisors (1).
125412402301 is an equidigital number, since it uses as much as digits as its factorization.
125412402301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1920, while the sum is 25.
Adding to 125412402301 its reverse (103204214521), we get a palindrome (228616616822).
The spelling of 125412402301 in words is "one hundred twenty-five billion, four hundred twelve million, four hundred two thousand, three hundred one".
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