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125420632697 is a prime number
BaseRepresentation
bin111010011001110100…
…1101111101001111001
3102222201210001021122102
41310303221233221321
54023330140221242
6133341211233145
712030016534163
oct1646351575171
9388653037572
10125420632697
114921074a758
12203831487b5
13ba9a22c939
1460db21d933
1533e0ce8e32
hex1d33a6fa79

125420632697 has 2 divisors, whose sum is σ = 125420632698. Its totient is φ = 125420632696.

The previous prime is 125420632693. The next prime is 125420632703. The reversal of 125420632697 is 796236024521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 116810834176 + 8609798521 = 341776^2 + 92789^2 .

It is a cyclic number.

It is not a de Polignac number, because 125420632697 - 22 = 125420632693 is a prime.

It is a super-2 number, since 2×1254206326972 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (125420632693) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62710316348 + 62710316349.

It is an arithmetic number, because the mean of its divisors is an integer number (62710316349).

Almost surely, 2125420632697 is an apocalyptic number.

It is an amenable number.

125420632697 is a deficient number, since it is larger than the sum of its proper divisors (1).

125420632697 is an equidigital number, since it uses as much as digits as its factorization.

125420632697 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1088640, while the sum is 47.

The spelling of 125420632697 in words is "one hundred twenty-five billion, four hundred twenty million, six hundred thirty-two thousand, six hundred ninety-seven".