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125433003011 = 209475988113
BaseRepresentation
bin111010011010001100…
…0111011110000000011
3102222202122022202112012
41310310120323300003
54023341322044021
6133342332323135
712030226635221
oct1646430736003
9388678282465
10125433003011
1149217729758
12203873134ab
13ba9c971354
1460dcb1db11
1533e1e3e35b
hex1d3463bc03

125433003011 has 4 divisors (see below), whose sum is σ = 125439012072. Its totient is φ = 125426993952.

The previous prime is 125433003001. The next prime is 125433003013. The reversal of 125433003011 is 110300334521.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-125433003011 is a prime.

It is a super-2 number, since 2×1254330030112 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (125433003013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2973110 + ... + 3015003.

It is an arithmetic number, because the mean of its divisors is an integer number (31359753018).

Almost surely, 2125433003011 is an apocalyptic number.

125433003011 is a deficient number, since it is larger than the sum of its proper divisors (6009061).

125433003011 is an equidigital number, since it uses as much as digits as its factorization.

125433003011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6009060.

The product of its (nonzero) digits is 1080, while the sum is 23.

Adding to 125433003011 its reverse (110300334521), we get a palindrome (235733337532).

The spelling of 125433003011 in words is "one hundred twenty-five billion, four hundred thirty-three million, three thousand, eleven".

Divisors: 1 20947 5988113 125433003011