Search a number
-
+
12543355234 = 26271677617
BaseRepresentation
bin10111010111010010…
…00110100101100010
31012101011112110121101
423223221012211202
5201142044331414
65432355345014
7622556521534
oct135351064542
935334473541
1012543355234
115357440493
1225208b216a
13124b8b96b7
1486dc5b854
154d62eea74
hex2eba46962

12543355234 has 4 divisors (see below), whose sum is σ = 18815032854. Its totient is φ = 6271677616.

The previous prime is 12543355207. The next prime is 12543355241. The reversal of 12543355234 is 43255334521.

12543355234 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 12543328009 + 27225 = 111997^2 + 165^2 .

It is a junction number, because it is equal to n+sod(n) for n = 12543355193 and 12543355202.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3135838807 + ... + 3135838810.

Almost surely, 212543355234 is an apocalyptic number.

12543355234 is a deficient number, since it is larger than the sum of its proper divisors (6271677620).

12543355234 is an equidigital number, since it uses as much as digits as its factorization.

12543355234 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6271677619.

The product of its digits is 216000, while the sum is 37.

Adding to 12543355234 its reverse (43255334521), we get a palindrome (55798689755).

The spelling of 12543355234 in words is "twelve billion, five hundred forty-three million, three hundred fifty-five thousand, two hundred thirty-four".

Divisors: 1 2 6271677617 12543355234