12544053433 has 4 divisors (see below), whose sum is σ = 12546229840. Its totient is φ = 12541877028.

The previous prime is 12544053419. The next prime is 12544053491. The reversal of 12544053433 is 33435044521.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33435044521 = 2803 ⋅11928307.

It is a cyclic number.

It is not a de Polignac number, because 12544053433 - 2²⁹ = 12007182521 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12544053413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1079535 + ... + 1091092.

It is an arithmetic number, because the mean of its divisors is an integer number (3136557460).

Almost surely, 2^12544053433 is an apocalyptic number.

It is an amenable number.

12544053433 is a deficient number, since it is larger than the sum of its proper divisors (2176407).

12544053433 is an equidigital number, since it uses as much as digits as its factorization.

12544053433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2176406.

The product of its (nonzero) digits is 86400, while the sum is 34.

Adding to 12544053433 its reverse (33435044521), we get a palindrome (45979097954).

The spelling of 12544053433 in words is "twelve billion, five hundred forty-four million, fifty-three thousand, four hundred thirty-three".