Base | Representation |
---|---|
bin | 10010010000010001011… |
… | …100001011101100101101 |
3 | 11102220212220021112222222 |
4 | 102100101130023230231 |
5 | 131023024300113203 |
6 | 2400135103245125 |
7 | 156425526001244 |
oct | 22202134135455 |
9 | 4386786245888 |
10 | 1254423051053 |
11 | 443aa8122937 |
12 | 1831478a97a5 |
13 | 913a37cb7b3 |
14 | 44a0045395b |
15 | 2296ca1e038 |
hex | 1241170bb2d |
1254423051053 has 2 divisors, whose sum is σ = 1254423051054. Its totient is φ = 1254423051052.
The previous prime is 1254423051043. The next prime is 1254423051059. The reversal of 1254423051053 is 3501503244521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1236183738244 + 18239312809 = 1111838^2 + 135053^2 .
It is a cyclic number.
It is not a de Polignac number, because 1254423051053 - 236 = 1185703574317 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1254423051059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 627211525526 + 627211525527.
It is an arithmetic number, because the mean of its divisors is an integer number (627211525527).
Almost surely, 21254423051053 is an apocalyptic number.
It is an amenable number.
1254423051053 is a deficient number, since it is larger than the sum of its proper divisors (1).
1254423051053 is an equidigital number, since it uses as much as digits as its factorization.
1254423051053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72000, while the sum is 35.
Adding to 1254423051053 its reverse (3501503244521), we get a palindrome (4755926295574).
The spelling of 1254423051053 in words is "one trillion, two hundred fifty-four billion, four hundred twenty-three million, fifty-one thousand, fifty-three".
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