12544340141 has 4 divisors (see below), whose sum is σ = 12549444000. Its totient is φ = 12539236284.

The previous prime is 12544340131. The next prime is 12544340143. The reversal of 12544340141 is 14104344521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14104344521 = 30577 ⋅461273.

It is a cyclic number.

It is not a de Polignac number, because 12544340141 - 2²² = 12540145837 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12544340143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2548241 + ... + 2553158.

It is an arithmetic number, because the mean of its divisors is an integer number (3137361000).

Almost surely, 2^12544340141 is an apocalyptic number.

It is an amenable number.

12544340141 is a deficient number, since it is larger than the sum of its proper divisors (5103859).

12544340141 is an equidigital number, since it uses as much as digits as its factorization.

12544340141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5103858.

The product of its (nonzero) digits is 7680, while the sum is 29.

Adding to 12544340141 its reverse (14104344521), we get a palindrome (26648684662).

The spelling of 12544340141 in words is "twelve billion, five hundred forty-four million, three hundred forty thousand, one hundred forty-one".