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12544411442471 is a prime number
BaseRepresentation
bin1011011010001011100100…
…1100000001110100100111
31122102020022121020211221122
42312202321030001310213
53121011423312124341
642402453440404155
72433206131636106
oct266427114016447
948366277224848
1012544411442471
113aa7067255367
1214a723601665b
136ccc1882b1ac
1431521d22603d
1516b49798494b
hexb68b9301d27

12544411442471 has 2 divisors, whose sum is σ = 12544411442472. Its totient is φ = 12544411442470.

The previous prime is 12544411442449. The next prime is 12544411442489. The reversal of 12544411442471 is 17424411444521.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12544411442471 is a prime.

It is a super-3 number, since 3×125444114424713 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12544411442411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6272205721235 + 6272205721236.

It is an arithmetic number, because the mean of its divisors is an integer number (6272205721236).

Almost surely, 212544411442471 is an apocalyptic number.

12544411442471 is a deficient number, since it is larger than the sum of its proper divisors (1).

12544411442471 is an equidigital number, since it uses as much as digits as its factorization.

12544411442471 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 573440, while the sum is 44.

Adding to 12544411442471 its reverse (17424411444521), we get a palindrome (29968822886992).

The spelling of 12544411442471 in words is "twelve trillion, five hundred forty-four billion, four hundred eleven million, four hundred forty-two thousand, four hundred seventy-one".