12544411444471 has 2 divisors, whose sum is σ = 12544411444472. Its totient is φ = 12544411444470.

The previous prime is 12544411444447. The next prime is 12544411444519. The reversal of 12544411444471 is 17444411444521.

12544411444471 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12544411444471 is a prime.

It is a super-3 number, since 3×12544411444471³ (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12544411444441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6272205722235 + 6272205722236.

It is an arithmetic number, because the mean of its divisors is an integer number (6272205722236).

Almost surely, 2^{12544411444471} is an apocalyptic number.

12544411444471 is a deficient number, since it is larger than the sum of its proper divisors (1).

12544411444471 is an equidigital number, since it uses as much as digits as its factorization.

12544411444471 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1146880, while the sum is 46.

Adding to 12544411444471 its reverse (17444411444521), we get a palindrome (29988822888992).

The spelling of 12544411444471 in words is "twelve trillion, five hundred forty-four billion, four hundred eleven million, four hundred forty-four thousand, four hundred seventy-one".