Base | Representation |
---|---|
bin | 111010011011111011… |
… | …0100111000010000011 |
3 | 102222220200200002222022 |
4 | 1310313312213002003 |
5 | 4024001211122430 |
6 | 133352210032055 |
7 | 12031533604313 |
oct | 1646766470203 |
9 | 388820602868 |
10 | 125491114115 |
11 | 4924750a464 |
12 | 203a287862b |
13 | baaba09613 |
14 | 6106729443 |
15 | 33e70bc4e5 |
hex | 1d37da7083 |
125491114115 has 4 divisors (see below), whose sum is σ = 150589336944. Its totient is φ = 100392891288.
The previous prime is 125491114103. The next prime is 125491114117. The reversal of 125491114115 is 511411194521.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 125491114115 - 210 = 125491113091 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (125491114117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12549111407 + ... + 12549111416.
It is an arithmetic number, because the mean of its divisors is an integer number (37647334236).
Almost surely, 2125491114115 is an apocalyptic number.
125491114115 is a deficient number, since it is larger than the sum of its proper divisors (25098222829).
125491114115 is an equidigital number, since it uses as much as digits as its factorization.
125491114115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25098222828.
The product of its digits is 7200, while the sum is 35.
The spelling of 125491114115 in words is "one hundred twenty-five billion, four hundred ninety-one million, one hundred fourteen thousand, one hundred fifteen".
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