Base | Representation |
---|---|
bin | 10010010000110100000… |
… | …101110110101101011111 |
3 | 11102222101102012011111012 |
4 | 102100310011312231133 |
5 | 131030222111303404 |
6 | 2400312511445435 |
7 | 156446115251444 |
oct | 22206405665537 |
9 | 4388342164435 |
10 | 1255004400479 |
11 | 4442762a2305 |
12 | 18328a52687b |
13 | 9146709723b |
14 | 44a577439cb |
15 | 229a3aa5a6e |
hex | 12434176b5f |
1255004400479 has 2 divisors, whose sum is σ = 1255004400480. Its totient is φ = 1255004400478.
The previous prime is 1255004400359. The next prime is 1255004400493. The reversal of 1255004400479 is 9740044005521.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1255004400479 - 212 = 1255004396383 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1255004400079) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 627502200239 + 627502200240.
It is an arithmetic number, because the mean of its divisors is an integer number (627502200240).
Almost surely, 21255004400479 is an apocalyptic number.
1255004400479 is a deficient number, since it is larger than the sum of its proper divisors (1).
1255004400479 is an equidigital number, since it uses as much as digits as its factorization.
1255004400479 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 201600, while the sum is 41.
The spelling of 1255004400479 in words is "one trillion, two hundred fifty-five billion, four million, four hundred thousand, four hundred seventy-nine".
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