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1255024410053 is a prime number
BaseRepresentation
bin10010010000110101010…
…010001011110111000101
311102222102210211202110112
4102100311102023313011
5131030242222110203
62400314504402405
7156446450320421
oct22206522136705
94388383752415
101255024410053
11444286619847
12183295176405
139146b281b1b
1444a5a271b81
15229a57096d8
hex1243548bdc5

1255024410053 has 2 divisors, whose sum is σ = 1255024410054. Its totient is φ = 1255024410052.

The previous prime is 1255024409999. The next prime is 1255024410097. The reversal of 1255024410053 is 3500144205521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1169410820449 + 85613589604 = 1081393^2 + 292598^2 .

It is an emirp because it is prime and its reverse (3500144205521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1255024410053 - 28 = 1255024409797 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1255024410953) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 627512205026 + 627512205027.

It is an arithmetic number, because the mean of its divisors is an integer number (627512205027).

Almost surely, 21255024410053 is an apocalyptic number.

It is an amenable number.

1255024410053 is a deficient number, since it is larger than the sum of its proper divisors (1).

1255024410053 is an equidigital number, since it uses as much as digits as its factorization.

1255024410053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24000, while the sum is 32.

Adding to 1255024410053 its reverse (3500144205521), we get a palindrome (4755168615574).

The spelling of 1255024410053 in words is "one trillion, two hundred fifty-five billion, twenty-four million, four hundred ten thousand, fifty-three".