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1255240117 is a prime number
BaseRepresentation
bin100101011010001…
…0111000110110101
310020110221210201201
41022310113012311
510032320140432
6324320052501
743051236115
oct11264270665
93213853651
101255240117
1159460652a
122b0464131
13170095a41
14bc9cd045
15752ecee7
hex4ad171b5

1255240117 has 2 divisors, whose sum is σ = 1255240118. Its totient is φ = 1255240116.

The previous prime is 1255240099. The next prime is 1255240121. The reversal of 1255240117 is 7110425521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1073152081 + 182088036 = 32759^2 + 13494^2 .

It is an emirp because it is prime and its reverse (7110425521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1255240117 - 223 = 1246851509 is a prime.

It is a super-3 number, since 3×12552401173 (a number of 28 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1255243117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 627620058 + 627620059.

It is an arithmetic number, because the mean of its divisors is an integer number (627620059).

Almost surely, 21255240117 is an apocalyptic number.

It is an amenable number.

1255240117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1255240117 is an equidigital number, since it uses as much as digits as its factorization.

1255240117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2800, while the sum is 28.

The square root of 1255240117 is about 35429.3680017016. The cubic root of 1255240117 is about 1078.7205118093.

Adding to 1255240117 its reverse (7110425521), we get a palindrome (8365665638).

The spelling of 1255240117 in words is "one billion, two hundred fifty-five million, two hundred forty thousand, one hundred seventeen".