Base | Representation |
---|---|
bin | 10010010001001000000… |
… | …111000010010010000111 |
3 | 11110000020211011022101012 |
4 | 102101020013002102013 |
5 | 131031414101114333 |
6 | 2400410110152435 |
7 | 156460334050310 |
oct | 22211007022207 |
9 | 4400224138335 |
10 | 1255340254343 |
11 | 44442893528a |
12 | 183362ab271b |
13 | 914bb839636 |
14 | 44a8a1ab607 |
15 | 229c32e7e48 |
hex | 124481c2487 |
1255340254343 has 4 divisors (see below), whose sum is σ = 1434674576400. Its totient is φ = 1076005932288.
The previous prime is 1255340254327. The next prime is 1255340254349. The reversal of 1255340254343 is 3434520435521.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1255340254343 - 24 = 1255340254327 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1255340254343.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1255340254349) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 89667161018 + ... + 89667161031.
It is an arithmetic number, because the mean of its divisors is an integer number (358668644100).
Almost surely, 21255340254343 is an apocalyptic number.
1255340254343 is a deficient number, since it is larger than the sum of its proper divisors (179334322057).
1255340254343 is an equidigital number, since it uses as much as digits as its factorization.
1255340254343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 179334322056.
The product of its (nonzero) digits is 864000, while the sum is 41.
Adding to 1255340254343 its reverse (3434520435521), we get a palindrome (4689860689864).
The spelling of 1255340254343 in words is "one trillion, two hundred fifty-five billion, three hundred forty million, two hundred fifty-four thousand, three hundred forty-three".
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