Search a number
-
+
12554351246741 is a prime number
BaseRepresentation
bin1011011010110000100110…
…1001010111110110010101
31122110011222022202020001112
42312230021221113312111
53121142302404343431
642411220033104405
72434010345610233
oct266541151276625
948404868666045
1012554351246741
1140002a7a95437
1214a914a9b8105
13700b40c00595
143158c3399953
1516b87a401c2b
hexb6b09a57d95

12554351246741 has 2 divisors, whose sum is σ = 12554351246742. Its totient is φ = 12554351246740.

The previous prime is 12554351246737. The next prime is 12554351246783. The reversal of 12554351246741 is 14764215345521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12553345024900 + 1006221841 = 3543070^2 + 31721^2 .

It is a cyclic number.

It is not a de Polignac number, because 12554351246741 - 22 = 12554351246737 is a prime.

It is a super-2 number, since 2×125543512467412 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12554351246741.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12554351246791) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6277175623370 + 6277175623371.

It is an arithmetic number, because the mean of its divisors is an integer number (6277175623371).

Almost surely, 212554351246741 is an apocalyptic number.

It is an amenable number.

12554351246741 is a deficient number, since it is larger than the sum of its proper divisors (1).

12554351246741 is an equidigital number, since it uses as much as digits as its factorization.

12554351246741 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4032000, while the sum is 50.

The spelling of 12554351246741 in words is "twelve trillion, five hundred fifty-four billion, three hundred fifty-one million, two hundred forty-six thousand, seven hundred forty-one".