Base | Representation |
---|---|
bin | 11100100010111010111001… |
… | …111111001100100000011011 |
3 | 121110111222121220200000001012 |
4 | 130202322321333030200123 |
5 | 112423412142142211324 |
6 | 1123002330003444135 |
7 | 35305220331054443 |
oct | 3442727177144033 |
9 | 543458556600035 |
10 | 125545014413339 |
11 | 37003383759164 |
12 | 120b756b38664b |
13 | 5508ac8528431 |
14 | 23005a817b123 |
15 | e7aaa97e420e |
hex | 722eb9fcc81b |
125545014413339 has 2 divisors, whose sum is σ = 125545014413340. Its totient is φ = 125545014413338.
The previous prime is 125545014413311. The next prime is 125545014413353. The reversal of 125545014413339 is 933314410545521.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 125545014413339 - 216 = 125545014347803 is a prime.
It is a super-2 number, since 2×1255450144133392 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (125545014413359) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62772507206669 + 62772507206670.
It is an arithmetic number, because the mean of its divisors is an integer number (62772507206670).
Almost surely, 2125545014413339 is an apocalyptic number.
125545014413339 is a deficient number, since it is larger than the sum of its proper divisors (1).
125545014413339 is an equidigital number, since it uses as much as digits as its factorization.
125545014413339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888000, while the sum is 50.
The spelling of 125545014413339 in words is "one hundred twenty-five trillion, five hundred forty-five billion, fourteen million, four hundred thirteen thousand, three hundred thirty-nine".
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