Base | Representation |
---|---|
bin | 11100100010111010111001… |
… | …111111001100011111111111 |
3 | 121110111222121220200000000011 |
4 | 130202322321333030133333 |
5 | 112423412142142211221 |
6 | 1123002330003444051 |
7 | 35305220331054403 |
oct | 3442727177143777 |
9 | 543458556600004 |
10 | 125545014413311 |
11 | 37003383759139 |
12 | 120b756b386627 |
13 | 5508ac852840c |
14 | 23005a817b103 |
15 | e7aaa97e41e1 |
hex | 722eb9fcc7ff |
125545014413311 has 2 divisors, whose sum is σ = 125545014413312. Its totient is φ = 125545014413310.
The previous prime is 125545014413261. The next prime is 125545014413339. The reversal of 125545014413311 is 113314410545521.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 125545014413311 - 239 = 124995258599423 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (125545714413311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62772507206655 + 62772507206656.
It is an arithmetic number, because the mean of its divisors is an integer number (62772507206656).
Almost surely, 2125545014413311 is an apocalyptic number.
125545014413311 is a deficient number, since it is larger than the sum of its proper divisors (1).
125545014413311 is an equidigital number, since it uses as much as digits as its factorization.
125545014413311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144000, while the sum is 40.
Adding to 125545014413311 its reverse (113314410545521), we get a palindrome (238859424958832).
The spelling of 125545014413311 in words is "one hundred twenty-five trillion, five hundred forty-five billion, fourteen million, four hundred thirteen thousand, three hundred eleven".
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