Base | Representation |
---|---|
bin | 11100100011000001110010… |
… | …111010110000010001000000 |
3 | 121110112200201110112102001010 |
4 | 130203001302322300101000 |
5 | 112424022314433020334 |
6 | 1123005552023440520 |
7 | 35305601545401426 |
oct | 3443016272602100 |
9 | 543480643472033 |
10 | 125552412001344 |
11 | 3700652a480559 |
12 | 120b8a948b6140 |
13 | 5509707009b43 |
14 | 2300aaa831116 |
15 | e7ad8de970e9 |
hex | 723072eb0440 |
125552412001344 has 28 divisors (see below), whose sum is σ = 332190756754064. Its totient is φ = 41850804000384.
The previous prime is 125552412001333. The next prime is 125552412001441. The reversal of 125552412001344 is 443100214255521.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 326959406062 + ... + 326959406445.
Almost surely, 2125552412001344 is an apocalyptic number.
It is an amenable number.
125552412001344 is an abundant number, since it is smaller than the sum of its proper divisors (206638344752720).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
125552412001344 is an equidigital number, since it uses as much as digits as its factorization.
125552412001344 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 653918812522 (or 653918812512 counting only the distinct ones).
The product of its (nonzero) digits is 192000, while the sum is 39.
Adding to 125552412001344 its reverse (443100214255521), we get a palindrome (568652626256865).
The spelling of 125552412001344 in words is "one hundred twenty-five trillion, five hundred fifty-two billion, four hundred twelve million, one thousand, three hundred forty-four".
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