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12555440432323 is a prime number
BaseRepresentation
bin1011011010110100101010…
…0100010010010011000011
31122110021210020020120210021
42312231022210102103003
53121202020222313243
642411520102114311
72434046342542345
oct266551244222303
948407706216707
1012555440432323
114000806893708
1214a93b371b997
13700c85765aa9
14315987cc1295
1516b8e0d4d6ed
hexb6b4a9124c3

12555440432323 has 2 divisors, whose sum is σ = 12555440432324. Its totient is φ = 12555440432322.

The previous prime is 12555440432321. The next prime is 12555440432363. The reversal of 12555440432323 is 32323404455521.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12555440432323 - 21 = 12555440432321 is a prime.

It is a super-2 number, since 2×125554404323232 (a number of 27 digits) contains 22 as substring.

Together with 12555440432321, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 12555440432323.

It is not a weakly prime, because it can be changed into another prime (12555440432321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6277720216161 + 6277720216162.

It is an arithmetic number, because the mean of its divisors is an integer number (6277720216162).

Almost surely, 212555440432323 is an apocalyptic number.

12555440432323 is a deficient number, since it is larger than the sum of its proper divisors (1).

12555440432323 is an equidigital number, since it uses as much as digits as its factorization.

12555440432323 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728000, while the sum is 43.

Adding to 12555440432323 its reverse (32323404455521), we get a palindrome (44878844887844).

The spelling of 12555440432323 in words is "twelve trillion, five hundred fifty-five billion, four hundred forty million, four hundred thirty-two thousand, three hundred twenty-three".