1255661315301 has 4 divisors (see below), whose sum is σ = 1674215087072. Its totient is φ = 837107543532.

The previous prime is 1255661315297. The next prime is 1255661315323. The reversal of 1255661315301 is 1035131665521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1255661315301 - 2² = 1255661315297 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1255661315301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1255661315341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 209276885881 + ... + 209276885886.

It is an arithmetic number, because the mean of its divisors is an integer number (418553771768).

Almost surely, 2^{1255661315301} is an apocalyptic number.

It is an amenable number.

1255661315301 is a deficient number, since it is larger than the sum of its proper divisors (418553771771).

1255661315301 is an equidigital number, since it uses as much as digits as its factorization.

1255661315301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 418553771770.

The product of its (nonzero) digits is 81000, while the sum is 39.

The spelling of 1255661315301 in words is "one trillion, two hundred fifty-five billion, six hundred sixty-one million, three hundred fifteen thousand, three hundred one".