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12560260478273 is a prime number
BaseRepresentation
bin1011011011000110100111…
…0111010011010101000001
31122110202020011000021210122
42312301221313103111001
53121241403140301043
642414034244310025
72434306651342424
oct266615167232501
948422204007718
1012560260478273
11400285a65a562
1214aa3199a2315
137015732386a1
14315cc40db9bb
1516bac40aa368
hexb6c69dd3541

12560260478273 has 2 divisors, whose sum is σ = 12560260478274. Its totient is φ = 12560260478272.

The previous prime is 12560260478153. The next prime is 12560260478287. The reversal of 12560260478273 is 37287406206521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12477651946384 + 82608531889 = 3532372^2 + 287417^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12560260478273 is a prime.

It is not a weakly prime, because it can be changed into another prime (12560260472273) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6280130239136 + 6280130239137.

It is an arithmetic number, because the mean of its divisors is an integer number (6280130239137).

Almost surely, 212560260478273 is an apocalyptic number.

It is an amenable number.

12560260478273 is a deficient number, since it is larger than the sum of its proper divisors (1).

12560260478273 is an equidigital number, since it uses as much as digits as its factorization.

12560260478273 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6773760, while the sum is 53.

The spelling of 12560260478273 in words is "twelve trillion, five hundred sixty billion, two hundred sixty million, four hundred seventy-eight thousand, two hundred seventy-three".