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12561303143 = 47267261769
BaseRepresentation
bin10111011001011011…
…00100011001100111
31012102102022022111202
423230231210121213
5201211143200033
65434240153115
7623165213024
oct135455443147
935372268452
1012561303143
115366589a74
12252690879b
131252531a6c
148723b054b
154d7b978e8
hex2ecb64667

12561303143 has 4 divisors (see below), whose sum is σ = 12828564960. Its totient is φ = 12294041328.

The previous prime is 12561303121. The next prime is 12561303149. The reversal of 12561303143 is 34130316521.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12561303143 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12561303149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 133630838 + ... + 133630931.

It is an arithmetic number, because the mean of its divisors is an integer number (3207141240).

Almost surely, 212561303143 is an apocalyptic number.

12561303143 is a deficient number, since it is larger than the sum of its proper divisors (267261817).

12561303143 is an equidigital number, since it uses as much as digits as its factorization.

12561303143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 267261816.

The product of its (nonzero) digits is 6480, while the sum is 29.

Adding to 12561303143 its reverse (34130316521), we get a palindrome (46691619664).

The spelling of 12561303143 in words is "twelve billion, five hundred sixty-one million, three hundred three thousand, one hundred forty-three".

Divisors: 1 47 267261769 12561303143