Base | Representation |
---|---|
bin | 1011011011001011111110… |
… | …1011100001001111111111 |
3 | 1122110212221111011021001222 |
4 | 2312302333223201033333 |
5 | 3121302330224331033 |
6 | 42414433155223555 |
7 | 2434360433130641 |
oct | 266627753411777 |
9 | 48425844137058 |
10 | 12561700230143 |
11 | 400342932a439 |
12 | 14aa65bba7bbb |
13 | 7017425c4a7c |
14 | 315dbd3da891 |
15 | 16bb5a6a3598 |
hex | b6cbfae13ff |
12561700230143 has 4 divisors (see below), whose sum is σ = 12562305546528. Its totient is φ = 12561094913760.
The previous prime is 12561700230017. The next prime is 12561700230151. The reversal of 12561700230143 is 34103200716521.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12561700230143 - 222 = 12561696035839 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12561700230943) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 302627063 + ... + 302668568.
It is an arithmetic number, because the mean of its divisors is an integer number (3140576386632).
Almost surely, 212561700230143 is an apocalyptic number.
12561700230143 is a deficient number, since it is larger than the sum of its proper divisors (605316385).
12561700230143 is an equidigital number, since it uses as much as digits as its factorization.
12561700230143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 605316384.
The product of its (nonzero) digits is 30240, while the sum is 35.
Adding to 12561700230143 its reverse (34103200716521), we get a palindrome (46664900946664).
The spelling of 12561700230143 in words is "twelve trillion, five hundred sixty-one billion, seven hundred million, two hundred thirty thousand, one hundred forty-three".
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