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125652700193 is a prime number
BaseRepresentation
bin111010100000101111…
…1000000110000100001
3110000022221201112101212
41311001133000300201
54024314042401233
6133420221235505
712035535220616
oct1650137006041
9400287645355
10125652700193
114931a745479
1220428a02b95
13bb06333c97
14611dd8c50d
153406389a48
hex1d417c0c21

125652700193 has 2 divisors, whose sum is σ = 125652700194. Its totient is φ = 125652700192.

The previous prime is 125652700189. The next prime is 125652700319. The reversal of 125652700193 is 391007256521.

Together with next prime (125652700319) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 117489216289 + 8163483904 = 342767^2 + 90352^2 .

It is a cyclic number.

It is not a de Polignac number, because 125652700193 - 22 = 125652700189 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 125652700193.

It is not a weakly prime, because it can be changed into another prime (125652700163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62826350096 + 62826350097.

It is an arithmetic number, because the mean of its divisors is an integer number (62826350097).

Almost surely, 2125652700193 is an apocalyptic number.

It is an amenable number.

125652700193 is a deficient number, since it is larger than the sum of its proper divisors (1).

125652700193 is an equidigital number, since it uses as much as digits as its factorization.

125652700193 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 113400, while the sum is 41.

The spelling of 125652700193 in words is "one hundred twenty-five billion, six hundred fifty-two million, seven hundred thousand, one hundred ninety-three".