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125652700319 is a prime number
BaseRepresentation
bin111010100000101111…
…1000000110010011111
3110000022221201112120112
41311001133000302133
54024314042402234
6133420221240235
712035535221156
oct1650137006237
9400287645515
10125652700319
114931a745583
1220428a0307b
13bb06334063
14611dd8c59d
153406389ace
hex1d417c0c9f

125652700319 has 2 divisors, whose sum is σ = 125652700320. Its totient is φ = 125652700318.

The previous prime is 125652700193. The next prime is 125652700333. The reversal of 125652700319 is 913007256521.

Together with previous prime (125652700193) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is an emirp because it is prime and its reverse (913007256521) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-125652700319 is a prime.

It is a super-2 number, since 2×1256527003192 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (125652700339) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62826350159 + 62826350160.

It is an arithmetic number, because the mean of its divisors is an integer number (62826350160).

Almost surely, 2125652700319 is an apocalyptic number.

125652700319 is a deficient number, since it is larger than the sum of its proper divisors (1).

125652700319 is an equidigital number, since it uses as much as digits as its factorization.

125652700319 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 113400, while the sum is 41.

The spelling of 125652700319 in words is "one hundred twenty-five billion, six hundred fifty-two million, seven hundred thousand, three hundred nineteen".