125659401341 has 2 divisors, whose sum is σ = 125659401342. Its totient is φ = 125659401340.

The previous prime is 125659401317. The next prime is 125659401379. The reversal of 125659401341 is 143104956521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 123783645241 + 1875756100 = 351829^2 + 43310^2 .

It is a cyclic number.

It is not a de Polignac number, because 125659401341 - 2¹⁸ = 125659139197 is a prime.

It is a super-3 number, since 3×125659401341³ (a number of 34 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (125659401311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62829700670 + 62829700671.

It is an arithmetic number, because the mean of its divisors is an integer number (62829700671).

Almost surely, 2^125659401341 is an apocalyptic number.

It is an amenable number.

125659401341 is a deficient number, since it is larger than the sum of its proper divisors (1).

125659401341 is an equidigital number, since it uses as much as digits as its factorization.

125659401341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 129600, while the sum is 41.

The spelling of 125659401341 in words is "one hundred twenty-five billion, six hundred fifty-nine million, four hundred one thousand, three hundred forty-one".