Base | Representation |
---|---|
bin | 111010100100101101… |
… | …0100110100101010101 |
3 | 110000200020002210001212 |
4 | 1311021122212211111 |
5 | 4030102123342013 |
6 | 133441333231205 |
7 | 12042042223403 |
oct | 1651132464525 |
9 | 400606083055 |
10 | 125785762133 |
11 | 49388868919 |
12 | 20465492505 |
13 | bb27a82365 |
14 | 6133908473 |
15 | 3412dc06a8 |
hex | 1d496a6955 |
125785762133 has 2 divisors, whose sum is σ = 125785762134. Its totient is φ = 125785762132.
The previous prime is 125785762103. The next prime is 125785762139. The reversal of 125785762133 is 331267587521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 124254840004 + 1530922129 = 352498^2 + 39127^2 .
It is a cyclic number.
It is not a de Polignac number, because 125785762133 - 214 = 125785745749 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (125785762139) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62892881066 + 62892881067.
It is an arithmetic number, because the mean of its divisors is an integer number (62892881067).
Almost surely, 2125785762133 is an apocalyptic number.
It is an amenable number.
125785762133 is a deficient number, since it is larger than the sum of its proper divisors (1).
125785762133 is an equidigital number, since it uses as much as digits as its factorization.
125785762133 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2116800, while the sum is 50.
The spelling of 125785762133 in words is "one hundred twenty-five billion, seven hundred eighty-five million, seven hundred sixty-two thousand, one hundred thirty-three".
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