Search a number
-
+
12596458409 is a prime number
BaseRepresentation
bin10111011101100111…
…01011001110101001
31012111212110101110122
423232303223032221
5201244143132114
65441533453025
7624103062353
oct135663531651
935455411418
1012596458409
115384410707
122536641175
1312598c03b2
14876d220d3
154dacdde8e
hex2eeceb3a9

12596458409 has 2 divisors, whose sum is σ = 12596458410. Its totient is φ = 12596458408.

The previous prime is 12596458393. The next prime is 12596458411. The reversal of 12596458409 is 90485469521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7440787600 + 5155670809 = 86260^2 + 71803^2 .

It is an emirp because it is prime and its reverse (90485469521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12596458409 - 24 = 12596458393 is a prime.

It is a super-2 number, since 2×125964584092 (a number of 21 digits) contains 22 as substring.

Together with 12596458411, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12596458429) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6298229204 + 6298229205.

It is an arithmetic number, because the mean of its divisors is an integer number (6298229205).

Almost surely, 212596458409 is an apocalyptic number.

It is an amenable number.

12596458409 is a deficient number, since it is larger than the sum of its proper divisors (1).

12596458409 is an equidigital number, since it uses as much as digits as its factorization.

12596458409 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3110400, while the sum is 53.

The spelling of 12596458409 in words is "twelve billion, five hundred ninety-six million, four hundred fifty-eight thousand, four hundred nine".