Base | Representation |
---|---|
bin | 11100101001101110001110… |
… | …011100011101110011100111 |
3 | 121112011200010021120111122020 |
4 | 130221232032130131303213 |
5 | 113004041431420333020 |
6 | 1124001151424034223 |
7 | 35354045422205553 |
oct | 3451561634356347 |
9 | 545150107514566 |
10 | 126012435324135 |
11 | 3717363466a748 |
12 | 12172079762973 |
13 | 5540bc9b80019 |
14 | 231906a5d8863 |
15 | e87d1519dc40 |
hex | 729b8e71dce7 |
126012435324135 has 16 divisors (see below), whose sum is σ = 202337405053920. Its totient is φ = 66967462661120.
The previous prime is 126012435324131. The next prime is 126012435324143. The reversal of 126012435324135 is 531423534210621.
It is not a de Polignac number, because 126012435324135 - 22 = 126012435324131 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (126012435324131) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14948090130 + ... + 14948098559.
It is an arithmetic number, because the mean of its divisors is an integer number (12646087815870).
Almost surely, 2126012435324135 is an apocalyptic number.
126012435324135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
126012435324135 is a deficient number, since it is larger than the sum of its proper divisors (76324969729785).
126012435324135 is a wasteful number, since it uses less digits than its factorization.
126012435324135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29896188978.
The product of its (nonzero) digits is 518400, while the sum is 42.
Adding to 126012435324135 its reverse (531423534210621), we get a palindrome (657435969534756).
The spelling of 126012435324135 in words is "one hundred twenty-six trillion, twelve billion, four hundred thirty-five million, three hundred twenty-four thousand, one hundred thirty-five".
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