1260349173953 has 2 divisors, whose sum is σ = 1260349173954. Its totient is φ = 1260349173952.

The previous prime is 1260349173899. The next prime is 1260349173983. The reversal of 1260349173953 is 3593719430621.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1259440573504 + 908600449 = 1122248^2 + 30143^2 .

It is a cyclic number.

It is not a de Polignac number, because 1260349173953 - 2¹² = 1260349169857 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1260349173895 and 1260349173904.

It is not a weakly prime, because it can be changed into another prime (1260349173983) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 630174586976 + 630174586977.

It is an arithmetic number, because the mean of its divisors is an integer number (630174586977).

Almost surely, 2^{1260349173953} is an apocalyptic number.

It is an amenable number.

1260349173953 is a deficient number, since it is larger than the sum of its proper divisors (1).

1260349173953 is an equidigital number, since it uses as much as digits as its factorization.

1260349173953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3674160, while the sum is 53.

The spelling of 1260349173953 in words is "one trillion, two hundred sixty billion, three hundred forty-nine million, one hundred seventy-three thousand, nine hundred fifty-three".