1260508970057 has 2 divisors, whose sum is σ = 1260508970058. Its totient is φ = 1260508970056.

The previous prime is 1260508970033. The next prime is 1260508970059. The reversal of 1260508970057 is 7500798050621.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1089645787321 + 170863182736 = 1043861^2 + 413356^2 .

It is a cyclic number.

It is not a de Polignac number, because 1260508970057 - 2¹⁴ = 1260508953673 is a prime.

Together with 1260508970059, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1260508969987 and 1260508970014.

It is not a weakly prime, because it can be changed into another prime (1260508970059) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 630254485028 + 630254485029.

It is an arithmetic number, because the mean of its divisors is an integer number (630254485029).

Almost surely, 2^{1260508970057} is an apocalyptic number.

It is an amenable number.

1260508970057 is a deficient number, since it is larger than the sum of its proper divisors (1).

1260508970057 is an equidigital number, since it uses as much as digits as its factorization.

1260508970057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1058400, while the sum is 50.

The spelling of 1260508970057 in words is "one trillion, two hundred sixty billion, five hundred eight million, nine hundred seventy thousand, fifty-seven".