Base | Representation |
---|---|
bin | 10111011111011000… |
… | …11100101110110001 |
3 | 1012112220110111212100 |
4 | 23233230130232301 |
5 | 201312000404413 |
6 | 5443224451013 |
7 | 624343426461 |
oct | 135754345661 |
9 | 35486414770 |
10 | 12611341233 |
11 | 5391856367 |
12 | 253b619a69 |
13 | 125ca015ba |
14 | 878cb7ba1 |
15 | 4dc27da73 |
hex | 2efb1cbb1 |
12611341233 has 6 divisors (see below), whose sum is σ = 18216381794. Its totient is φ = 8407560816.
The previous prime is 12611341213. The next prime is 12611341243. The reversal of 12611341233 is 33214311621.
It is a happy number.
12611341233 is a `hidden beast` number, since 1 + 2 + 611 + 3 + 4 + 12 + 33 = 666.
It can be written as a sum of positive squares in only one way, i.e., 8385431184 + 4225910049 = 91572^2 + 65007^2 .
It is not a de Polignac number, because 12611341233 - 213 = 12611333041 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12611341197 and 12611341206.
It is not an unprimeable number, because it can be changed into a prime (12611341213) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 700630060 + ... + 700630077.
Almost surely, 212611341233 is an apocalyptic number.
It is an amenable number.
12611341233 is a deficient number, since it is larger than the sum of its proper divisors (5605040561).
12611341233 is a wasteful number, since it uses less digits than its factorization.
12611341233 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1401260143 (or 1401260140 counting only the distinct ones).
The product of its digits is 2592, while the sum is 27.
Adding to 12611341233 its reverse (33214311621), we get a palindrome (45825652854).
The spelling of 12611341233 in words is "twelve billion, six hundred eleven million, three hundred forty-one thousand, two hundred thirty-three".
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