Base | Representation |
---|---|
bin | 10111011111100010… |
… | …00011111101000111 |
3 | 1012112222201221121221 |
4 | 23233301003331013 |
5 | 201312303103341 |
6 | 5443310421211 |
7 | 624356624113 |
oct | 135761037507 |
9 | 35488657557 |
10 | 12612550471 |
11 | 5392501934 |
12 | 253bb01807 |
13 | 1260035b21 |
14 | 879110743 |
15 | 4dc41bed1 |
hex | 2efc43f47 |
12612550471 has 2 divisors, whose sum is σ = 12612550472. Its totient is φ = 12612550470.
The previous prime is 12612550453. The next prime is 12612550513. The reversal of 12612550471 is 17405521621.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12612550471 - 219 = 12612026183 is a prime.
It is a super-3 number, since 3×126125504713 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12612550451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6306275235 + 6306275236.
It is an arithmetic number, because the mean of its divisors is an integer number (6306275236).
Almost surely, 212612550471 is an apocalyptic number.
12612550471 is a deficient number, since it is larger than the sum of its proper divisors (1).
12612550471 is an equidigital number, since it uses as much as digits as its factorization.
12612550471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16800, while the sum is 34.
The spelling of 12612550471 in words is "twelve billion, six hundred twelve million, five hundred fifty thousand, four hundred seventy-one".
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