Base | Representation |
---|---|
bin | 1011011110001010001011… |
… | …1010110011001100010011 |
3 | 1122122202201202001100112111 |
4 | 2313202202322303030103 |
5 | 3123121411332212313 |
6 | 42454115401410151 |
7 | 2441145612113626 |
oct | 267424272631423 |
9 | 48582652040474 |
10 | 12612757304083 |
11 | 4023049758812 |
12 | 14b852aa99957 |
13 | 7064bb365b21 |
14 | 318664293dbd |
15 | 16d147c5043d |
hex | b78a2eb3313 |
12612757304083 has 2 divisors, whose sum is σ = 12612757304084. Its totient is φ = 12612757304082.
The previous prime is 12612757304033. The next prime is 12612757304099. The reversal of 12612757304083 is 38040375721621.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12612757304083 - 213 = 12612757295891 is a prime.
It is a super-2 number, since 2×126127573040832 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12612757304003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6306378652041 + 6306378652042.
It is an arithmetic number, because the mean of its divisors is an integer number (6306378652042).
Almost surely, 212612757304083 is an apocalyptic number.
12612757304083 is a deficient number, since it is larger than the sum of its proper divisors (1).
12612757304083 is an equidigital number, since it uses as much as digits as its factorization.
12612757304083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1693440, while the sum is 49.
The spelling of 12612757304083 in words is "twelve trillion, six hundred twelve billion, seven hundred fifty-seven million, three hundred four thousand, eighty-three".
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