Base | Representation |
---|---|
bin | 1011011110010000011000… |
… | …1101011000001001011111 |
3 | 1122122221000211120111020012 |
4 | 2313210012031120021133 |
5 | 3123133314304242211 |
6 | 42454552545513435 |
7 | 2441235110235341 |
oct | 267440615301137 |
9 | 48587024514205 |
10 | 12614423118431 |
11 | 4023823aa1792 |
12 | 14b891494287b |
13 | 7066c55031a4 |
14 | 3187815db291 |
15 | 16d1e40eed8b |
hex | b790635825f |
12614423118431 has 2 divisors, whose sum is σ = 12614423118432. Its totient is φ = 12614423118430.
The previous prime is 12614423118383. The next prime is 12614423118497. The reversal of 12614423118431 is 13481132441621.
12614423118431 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12614423118431 is a prime.
It is a super-2 number, since 2×126144231184312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12614420118431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6307211559215 + 6307211559216.
It is an arithmetic number, because the mean of its divisors is an integer number (6307211559216).
Almost surely, 212614423118431 is an apocalyptic number.
12614423118431 is a deficient number, since it is larger than the sum of its proper divisors (1).
12614423118431 is an equidigital number, since it uses as much as digits as its factorization.
12614423118431 is an evil number, because the sum of its binary digits is even.
The product of its digits is 110592, while the sum is 41.
The spelling of 12614423118431 in words is "twelve trillion, six hundred fourteen billion, four hundred twenty-three million, one hundred eighteen thousand, four hundred thirty-one".
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