Base | Representation |
---|---|
bin | 1011011110111000100010… |
… | …0110110101100001001111 |
3 | 1122200221211221121122220121 |
4 | 2313232020212311201033 |
5 | 3123322402343440012 |
6 | 42503534232125411 |
7 | 2442066146563435 |
oct | 267561046654117 |
9 | 48627757548817 |
10 | 12625200765007 |
11 | 402835476a116 |
12 | 14baa22236867 |
13 | 707722347b5c |
14 | 3190c4b4ad55 |
15 | 16d6253bba07 |
hex | b7b889b584f |
12625200765007 has 2 divisors, whose sum is σ = 12625200765008. Its totient is φ = 12625200765006.
The previous prime is 12625200764999. The next prime is 12625200765049. The reversal of 12625200765007 is 70056700252621.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12625200765007 - 23 = 12625200764999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12625200765077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6312600382503 + 6312600382504.
It is an arithmetic number, because the mean of its divisors is an integer number (6312600382504).
Almost surely, 212625200765007 is an apocalyptic number.
12625200765007 is a deficient number, since it is larger than the sum of its proper divisors (1).
12625200765007 is an equidigital number, since it uses as much as digits as its factorization.
12625200765007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 352800, while the sum is 43.
The spelling of 12625200765007 in words is "twelve trillion, six hundred twenty-five billion, two hundred million, seven hundred sixty-five thousand, seven".
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