Base | Representation |
---|---|
bin | 11100101101111101011010… |
… | …100110000110100010001111 |
3 | 121120012111201122221210220101 |
4 | 130231331122212012202033 |
5 | 113023324310020224101 |
6 | 1124343030011031531 |
7 | 35414064345334561 |
oct | 3455753246064217 |
9 | 546174648853811 |
10 | 126303623211151 |
11 | 3727607a635041 |
12 | 121ba5a3a3b5a7 |
13 | 55624c4134399 |
14 | 23291b1273331 |
15 | e906a8de6401 |
hex | 72df5a98688f |
126303623211151 has 2 divisors, whose sum is σ = 126303623211152. Its totient is φ = 126303623211150.
The previous prime is 126303623211001. The next prime is 126303623211197. The reversal of 126303623211151 is 151112326303621.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 126303623211151 - 217 = 126303623080079 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 126303623211151.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (126303623214151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63151811605575 + 63151811605576.
It is an arithmetic number, because the mean of its divisors is an integer number (63151811605576).
Almost surely, 2126303623211151 is an apocalyptic number.
126303623211151 is a deficient number, since it is larger than the sum of its proper divisors (1).
126303623211151 is an equidigital number, since it uses as much as digits as its factorization.
126303623211151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38880, while the sum is 37.
Adding to 126303623211151 its reverse (151112326303621), we get a palindrome (277415949514772).
The spelling of 126303623211151 in words is "one hundred twenty-six trillion, three hundred three billion, six hundred twenty-three million, two hundred eleven thousand, one hundred fifty-one".
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