Base | Representation |
---|---|
bin | 1011011111010111110101… |
… | …1001001001010001110101 |
3 | 1122201202112111002010111012 |
4 | 2313311331121021101311 |
5 | 3123442104223424031 |
6 | 42511444043522005 |
7 | 2442514306636052 |
oct | 267657531112165 |
9 | 48652474063435 |
10 | 12633602561141 |
11 | 4030976319991 |
12 | 1500587b29305 |
13 | 708460baac63 |
14 | 319680926029 |
15 | 16d967cd2b2b |
hex | b7d7d649475 |
12633602561141 has 2 divisors, whose sum is σ = 12633602561142. Its totient is φ = 12633602561140.
The previous prime is 12633602561101. The next prime is 12633602561269. The reversal of 12633602561141 is 14116520633621.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11971226322916 + 662376238225 = 3459946^2 + 813865^2 .
It is a cyclic number.
It is not a de Polignac number, because 12633602561141 - 214 = 12633602544757 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12633602561101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6316801280570 + 6316801280571.
It is an arithmetic number, because the mean of its divisors is an integer number (6316801280571).
Almost surely, 212633602561141 is an apocalyptic number.
It is an amenable number.
12633602561141 is a deficient number, since it is larger than the sum of its proper divisors (1).
12633602561141 is an equidigital number, since it uses as much as digits as its factorization.
12633602561141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 155520, while the sum is 41.
The spelling of 12633602561141 in words is "twelve trillion, six hundred thirty-three billion, six hundred two million, five hundred sixty-one thousand, one hundred forty-one".
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