Base | Representation |
---|---|
bin | 11100101110101001110111… |
… | …011001111100111100110111 |
3 | 121120101001220220121010221201 |
4 | 130232221313121330330313 |
5 | 113030120031402040222 |
6 | 1124421002011353331 |
7 | 35420404161522646 |
oct | 3456516731747467 |
9 | 546331826533851 |
10 | 126351351205687 |
11 | 37294341867823 |
12 | 122078a3a52847 |
13 | 5566b5c28117a |
14 | 232b61bd4135d |
15 | e91a4e099427 |
hex | 72ea7767cf37 |
126351351205687 has 2 divisors, whose sum is σ = 126351351205688. Its totient is φ = 126351351205686.
The previous prime is 126351351205613. The next prime is 126351351205697. The reversal of 126351351205687 is 786502153153621.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 126351351205687 - 243 = 117555258183479 is a prime.
It is a super-2 number, since 2×1263513512056872 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (126351351205697) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63175675602843 + 63175675602844.
It is an arithmetic number, because the mean of its divisors is an integer number (63175675602844).
Almost surely, 2126351351205687 is an apocalyptic number.
126351351205687 is a deficient number, since it is larger than the sum of its proper divisors (1).
126351351205687 is an equidigital number, since it uses as much as digits as its factorization.
126351351205687 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9072000, while the sum is 55.
The spelling of 126351351205687 in words is "one hundred twenty-six trillion, three hundred fifty-one billion, three hundred fifty-one million, two hundred five thousand, six hundred eighty-seven".
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