Base | Representation |
---|---|
bin | 111010110101110001… |
… | …0110000011110001011 |
3 | 110002011010110222211211 |
4 | 1311223202300132023 |
5 | 4032240212401011 |
6 | 134014225233551 |
7 | 12062164020313 |
oct | 1655342603613 |
9 | 402133428754 |
10 | 126358325131 |
11 | 49651a86985 |
12 | 205a51928b7 |
13 | bbb959272c |
14 | 618998c443 |
15 | 34482bdb21 |
hex | 1d6b8b078b |
126358325131 has 2 divisors, whose sum is σ = 126358325132. Its totient is φ = 126358325130.
The previous prime is 126358325113. The next prime is 126358325167. The reversal of 126358325131 is 131523853621.
It is a happy number.
Together with previous prime (126358325113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 126358325131 - 25 = 126358325099 is a prime.
It is a super-2 number, since 2×1263583251312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (126358325111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63179162565 + 63179162566.
It is an arithmetic number, because the mean of its divisors is an integer number (63179162566).
Almost surely, 2126358325131 is an apocalyptic number.
126358325131 is a deficient number, since it is larger than the sum of its proper divisors (1).
126358325131 is an equidigital number, since it uses as much as digits as its factorization.
126358325131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 129600, while the sum is 40.
The spelling of 126358325131 in words is "one hundred twenty-six billion, three hundred fifty-eight million, three hundred twenty-five thousand, one hundred thirty-one".
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