Base | Representation |
---|---|
bin | 1011011111110100111000… |
… | …1111010100010000101101 |
3 | 1122202111122222221200122010 |
4 | 2313331032033110100231 |
5 | 3124104042223441000 |
6 | 42515213555511433 |
7 | 2443211465613564 |
oct | 267751617242055 |
9 | 48674588850563 |
10 | 12641401390125 |
11 | 40342085845a2 |
12 | 1501ba38b8579 |
13 | 709104846a71 |
14 | 319bc05c4bdb |
15 | 16dc727e1d50 |
hex | b7f4e3d442d |
12641401390125 has 16 divisors (see below), whose sum is σ = 21035291913792. Its totient is φ = 6742080741200.
The previous prime is 12641401390103. The next prime is 12641401390139. The reversal of 12641401390125 is 52109310414621.
It is not a de Polignac number, because 12641401390125 - 26 = 12641401390061 is a prime.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16855201479 + ... + 16855202228.
It is an arithmetic number, because the mean of its divisors is an integer number (1314705744612).
Almost surely, 212641401390125 is an apocalyptic number.
12641401390125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
12641401390125 is a deficient number, since it is larger than the sum of its proper divisors (8393890523667).
12641401390125 is an equidigital number, since it uses as much as digits as its factorization.
12641401390125 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 33710403725 (or 33710403715 counting only the distinct ones).
The product of its (nonzero) digits is 51840, while the sum is 39.
The spelling of 12641401390125 in words is "twelve trillion, six hundred forty-one billion, four hundred one million, three hundred ninety thousand, one hundred twenty-five".
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