Base | Representation |
---|---|
bin | 1011011111111001100101… |
… | …0111100000111101111011 |
3 | 1122202121220211200200210211 |
4 | 2313332121113200331323 |
5 | 3124114132412034043 |
6 | 42515543023251551 |
7 | 2443254642312124 |
oct | 267763127407573 |
9 | 48677824620724 |
10 | 12642661830523 |
11 | 40347a501207a |
12 | 1502295a49bb7 |
13 | 709275a1079a |
14 | 319c9db6904b |
15 | 16dce82baa9d |
hex | b7f995e0f7b |
12642661830523 has 2 divisors, whose sum is σ = 12642661830524. Its totient is φ = 12642661830522.
The previous prime is 12642661830517. The next prime is 12642661830529. The reversal of 12642661830523 is 32503816624621.
It is a balanced prime because it is at equal distance from previous prime (12642661830517) and next prime (12642661830529).
It is a cyclic number.
It is not a de Polignac number, because 12642661830523 - 233 = 12634071895931 is a prime.
It is not a weakly prime, because it can be changed into another prime (12642661830529) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6321330915261 + 6321330915262.
It is an arithmetic number, because the mean of its divisors is an integer number (6321330915262).
Almost surely, 212642661830523 is an apocalyptic number.
12642661830523 is a deficient number, since it is larger than the sum of its proper divisors (1).
12642661830523 is an equidigital number, since it uses as much as digits as its factorization.
12642661830523 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2488320, while the sum is 49.
The spelling of 12642661830523 in words is "twelve trillion, six hundred forty-two billion, six hundred sixty-one million, eight hundred thirty thousand, five hundred twenty-three".
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