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12642666024881 is a prime number
BaseRepresentation
bin1011011111111001100110…
…0111100000111110110001
31122202121221010120210101102
42313332121213200332301
53124114140000244011
642515543253214145
72443255023051434
oct267763147407661
948677833523342
1012642666024881
1140347a7417392
121502297331355
1370927684b959
14319ca053b81b
1516dce884873b
hexb7f999e0fb1

12642666024881 has 2 divisors, whose sum is σ = 12642666024882. Its totient is φ = 12642666024880.

The previous prime is 12642666024749. The next prime is 12642666024883. The reversal of 12642666024881 is 18842066624621.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7602102210481 + 5040563814400 = 2757191^2 + 2245120^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12642666024881 is a prime.

It is a super-2 number, since 2×126426660248812 (a number of 27 digits) contains 22 as substring.

Together with 12642666024883, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12642666024883) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6321333012440 + 6321333012441.

It is an arithmetic number, because the mean of its divisors is an integer number (6321333012441).

Almost surely, 212642666024881 is an apocalyptic number.

It is an amenable number.

12642666024881 is a deficient number, since it is larger than the sum of its proper divisors (1).

12642666024881 is an equidigital number, since it uses as much as digits as its factorization.

12642666024881 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10616832, while the sum is 56.

The spelling of 12642666024881 in words is "twelve trillion, six hundred forty-two billion, six hundred sixty-six million, twenty-four thousand, eight hundred eighty-one".