12648556023433 has 8 divisors (see below), whose sum is σ = 13803254477280. Its totient is φ = 11494662523680.

The previous prime is 12648556023431. The next prime is 12648556023469. The reversal of 12648556023433 is 33432065584621.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12648556023433 - 2¹ = 12648556023431 is a prime.

It is a super-3 number, since 3×12648556023433³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12648556023431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 201205663 + ... + 201268516.

It is an arithmetic number, because the mean of its divisors is an integer number (1725406809660).

Almost surely, 2^{12648556023433} is an apocalyptic number.

It is an amenable number.

12648556023433 is a deficient number, since it is larger than the sum of its proper divisors (1154698453847).

12648556023433 is a wasteful number, since it uses less digits than its factorization.

12648556023433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 402477047.

The product of its (nonzero) digits is 12441600, while the sum is 52.

The spelling of 12648556023433 in words is "twelve trillion, six hundred forty-eight billion, five hundred fifty-six million, twenty-three thousand, four hundred thirty-three".