Base | Representation |
---|---|
bin | 10010011010001010011… |
… | …101101100110000011010 |
3 | 11110221022001101112000110 |
4 | 102122022131230300122 |
5 | 131211302104120310 |
6 | 2405053010545150 |
7 | 160252645463415 |
oct | 22321235546032 |
9 | 4427261345013 |
10 | 1265043426330 |
11 | 448558041a92 |
12 | 1852105981b6 |
13 | 923a6b99a18 |
14 | 4532ab44b7c |
15 | 22d900c1d20 |
hex | 1268a76cc1a |
1265043426330 has 32 divisors (see below), whose sum is σ = 3040093902528. Its totient is φ = 336901616000.
The previous prime is 1265043426299. The next prime is 1265043426379. The reversal of 1265043426330 is 336243405621.
It is a super-2 number, since 2×12650434263302 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 27682896 + ... + 27728555.
It is an arithmetic number, because the mean of its divisors is an integer number (95002934454).
Almost surely, 21265043426330 is an apocalyptic number.
1265043426330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1265043426330 is an abundant number, since it is smaller than the sum of its proper divisors (1775050476198).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1265043426330 is a wasteful number, since it uses less digits than its factorization.
1265043426330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 55412222.
The product of its (nonzero) digits is 311040, while the sum is 39.
The spelling of 1265043426330 in words is "one trillion, two hundred sixty-five billion, forty-three million, four hundred twenty-six thousand, three hundred thirty".
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