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12651145403 = 13973165031
BaseRepresentation
bin10111100100001000…
…10010100010111011
31012122200100202220212
423302010102202323
5201402143123103
65451205541335
7625335650561
oct136204224273
935580322825
1012651145403
115402272876
122550a1484b
131268029c70
148802b9a31
154e09e27d8
hex2f21128bb

12651145403 has 4 divisors (see below), whose sum is σ = 13624310448. Its totient is φ = 11677980360.

The previous prime is 12651145379. The next prime is 12651145433. The reversal of 12651145403 is 30454115621.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12651145403 - 214 = 12651129019 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12651145403.

It is not an unprimeable number, because it can be changed into a prime (12651145433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 486582503 + ... + 486582528.

It is an arithmetic number, because the mean of its divisors is an integer number (3406077612).

Almost surely, 212651145403 is an apocalyptic number.

12651145403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

12651145403 is a deficient number, since it is larger than the sum of its proper divisors (973165045).

12651145403 is an equidigital number, since it uses as much as digits as its factorization.

12651145403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 973165044.

The product of its (nonzero) digits is 14400, while the sum is 32.

The spelling of 12651145403 in words is "twelve billion, six hundred fifty-one million, one hundred forty-five thousand, four hundred three".

Divisors: 1 13 973165031 12651145403