Base | Representation |
---|---|
bin | 10111100100010000… |
… | …01000101001011001 |
3 | 1012122202020222200022 |
4 | 23302020020221121 |
5 | 201402422402213 |
6 | 5451243320225 |
7 | 625350346463 |
oct | 136210105131 |
9 | 35582228608 |
10 | 12652153433 |
11 | 54028a1157 |
12 | 2551220075 |
13 | 12682c0a2a |
14 | 88049d133 |
15 | 4e0b41308 |
hex | 2f2208a59 |
12652153433 has 4 divisors (see below), whose sum is σ = 12701383860. Its totient is φ = 12602923008.
The previous prime is 12652153429. The next prime is 12652153453. The reversal of 12652153433 is 33435125621.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 6924236944 + 5727916489 = 83212^2 + 75683^2 .
It is a cyclic number.
It is not a de Polignac number, because 12652153433 - 22 = 12652153429 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12652153393 and 12652153402.
It is not an unprimeable number, because it can be changed into a prime (12652153453) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24614828 + ... + 24615341.
It is an arithmetic number, because the mean of its divisors is an integer number (3175345965).
Almost surely, 212652153433 is an apocalyptic number.
It is an amenable number.
12652153433 is a deficient number, since it is larger than the sum of its proper divisors (49230427).
12652153433 is an equidigital number, since it uses as much as digits as its factorization.
12652153433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49230426.
The product of its digits is 64800, while the sum is 35.
The spelling of 12652153433 in words is "twelve billion, six hundred fifty-two million, one hundred fifty-three thousand, four hundred thirty-three".
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