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12652648065131 is a prime number
BaseRepresentation
bin1011100000011110110010…
…0101111110100001101011
31122210120200210112222100212
42320013230211332201223
53124300110401041011
642524313555051335
72444060262022544
oct270075445764153
948716623488325
1012652648065131
114038a59a84a28
1215042022a0b4b
1370a1a78bb549
1431a56a1474cb
1516e1ced5a08b
hexb81ec97e86b

12652648065131 has 2 divisors, whose sum is σ = 12652648065132. Its totient is φ = 12652648065130.

The previous prime is 12652648065077. The next prime is 12652648065133. The reversal of 12652648065131 is 13156084625621.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12652648065131 - 242 = 8254601554027 is a prime.

It is a super-2 number, since 2×126526480651312 (a number of 27 digits) contains 22 as substring.

Together with 12652648065133, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12652648065131.

It is not a weakly prime, because it can be changed into another prime (12652648065133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6326324032565 + 6326324032566.

It is an arithmetic number, because the mean of its divisors is an integer number (6326324032566).

Almost surely, 212652648065131 is an apocalyptic number.

12652648065131 is a deficient number, since it is larger than the sum of its proper divisors (1).

12652648065131 is an equidigital number, since it uses as much as digits as its factorization.

12652648065131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2073600, while the sum is 50.

The spelling of 12652648065131 in words is "twelve trillion, six hundred fifty-two billion, six hundred forty-eight million, sixty-five thousand, one hundred thirty-one".