Base | Representation |
---|---|
bin | 10111100100100110… |
… | …00000000111101101 |
3 | 1012122221121201022020 |
4 | 23302103000013231 |
5 | 201404140031333 |
6 | 5451424340353 |
7 | 625413512556 |
oct | 136223000755 |
9 | 35587551266 |
10 | 12655002093 |
11 | 5404467418 |
12 | 25521746b9 |
13 | 1268a7a526 |
14 | 880a0132d |
15 | 4e10053b3 |
hex | 2f24c01ed |
12655002093 has 4 divisors (see below), whose sum is σ = 16873336128. Its totient is φ = 8436668060.
The previous prime is 12655002091. The next prime is 12655002103. The reversal of 12655002093 is 39020055621.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 39020055621 = 3 ⋅13006685207.
It is a cyclic number.
It is not a de Polignac number, because 12655002093 - 21 = 12655002091 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12655002091) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2109167013 + ... + 2109167018.
It is an arithmetic number, because the mean of its divisors is an integer number (4218334032).
Almost surely, 212655002093 is an apocalyptic number.
It is an amenable number.
12655002093 is a deficient number, since it is larger than the sum of its proper divisors (4218334035).
12655002093 is an equidigital number, since it uses as much as digits as its factorization.
12655002093 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4218334034.
The product of its (nonzero) digits is 16200, while the sum is 33.
The spelling of 12655002093 in words is "twelve billion, six hundred fifty-five million, two thousand, ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •