Base | Representation |
---|---|
bin | 111010111011111110… |
… | …0001010110010110111 |
3 | 110002200121211212202112 |
4 | 1311313330022302313 |
5 | 4033201434010033 |
6 | 134051015201235 |
7 | 12100300624334 |
oct | 1656774126267 |
9 | 402617755675 |
10 | 126566313143 |
11 | 497494253a6 |
12 | 2064297621b |
13 | bc206b586a |
14 | 61a944d98b |
15 | 345b6a4c48 |
hex | 1d77f0acb7 |
126566313143 has 2 divisors, whose sum is σ = 126566313144. Its totient is φ = 126566313142.
The previous prime is 126566313101. The next prime is 126566313257. The reversal of 126566313143 is 341313665621.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-126566313143 is a prime.
It is a super-2 number, since 2×1265663131432 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 126566313143.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (126566343143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63283156571 + 63283156572.
It is an arithmetic number, because the mean of its divisors is an integer number (63283156572).
Almost surely, 2126566313143 is an apocalyptic number.
126566313143 is a deficient number, since it is larger than the sum of its proper divisors (1).
126566313143 is an equidigital number, since it uses as much as digits as its factorization.
126566313143 is an evil number, because the sum of its binary digits is even.
The product of its digits is 233280, while the sum is 41.
Adding to 126566313143 its reverse (341313665621), we get a palindrome (467879978764).
The spelling of 126566313143 in words is "one hundred twenty-six billion, five hundred sixty-six million, three hundred thirteen thousand, one hundred forty-three".
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